Binary Tree Preorder Traversal

https://leetcode.com/problems/binary-tree-preorder-traversal/

Question

Given the root of a binary tree, return the preorder traversal of its nodes' values.

Example 1:

Input: root = [1,null,2,3]
Output: [1,2,3]

Answer

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def preorderTraversal(self, root: TreeNode) -> List[int]:
        to_ret = []
        def preorder(root):
            if not root:
                return
            to_ret.append(root.val)
            preorder(root.left)
            preorder(root.right)
        preorder(root)
        return to_ret

If the root node does not exist, return nothing.

Else perform preorder by:

• Appending the value

• Left recurse

• Right recurse