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Majority Vote

https://leetcode.com/problems/majority-element/

Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.

You may assume that the array is non-empty and the majority element always exist in the array.

Example 1:

Input: [3,2,3]
Output: 3

class Solution:
    def majorityElement(self, nums: List[int]) -> int:
        cnt = 0
        maj = 0
        for i in nums:
            if cnt == 0:
                maj = i
            cnt += 1 if maj == i else -1
        return maj

We increment the counter if we come across maj as the majority. Else we decrement it.

If we have 4 elements. 3 are "1" and 1 is "2". We will end up with 3 as the majority.

Note we need to perform another pass to count if it's truly the majority and has won by n/2 votes. This is guaranteed in this problem.

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Last updated 5 years ago